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krish1092 (551)

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Find the equations of the lines parallel to x-axis between which the graph of y=  lies.

    
ganesha1991 (1700)

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now slope of lines parallel to each other r equal

so slope of x-axis and the lines parallel to it must be equal

and sl;ope of x axis is 0


so the genrale equation of the line


is


(Y -y)=m(X-x)


m=0


therefore Y=y


i think i'm wrong can u tell the answer

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krish1092 (551)

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Answers are y=0 and y=1

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y=|12x/4x^2+9|
differentiating this
dy/dx=((12(4x^2+9)-8x(12x))/(4x^2+9)^2)
dy/dx=(108-48x^2)/(4x^2+9)^2)
but to find the stationary pts dy/dx=0

108=48x^2
+-3/2=x
i cannot proceed further, think this would be of some help

SHREYA
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spideyunlimited (4223)

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Find the equations of the lines parallel to x-axis between which the graph of y=  lies.


 



 This is of the form :


| 2ab / (a^2 + b^2) |   where a is 2x and b is 3.


And we know:


a^2 + b^2 >= 2ab


so | 2ab / (a^2 + b^2) |   <= 1


so y <= 1 


and y >= 0    ( x = 0 gives minimum value)


So the two boundary lines are y = 1 and y = 0


---------------------------------------------------------------

- Gaurav Ragtah (spideyunlimited)
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