Find the equations of the lines parallel to x-axis between which the graph of y=
lies.

This is of the form :
| 2ab / (a^2 + b^2) | where a is 2x and b is 3.
And we know:
a^2 + b^2 >= 2ab
so | 2ab / (a^2 + b^2) | <= 1
so y <= 1
and y >= 0 ( x = 0 gives minimum value)
So the two boundary lines are y = 1 and y = 0