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Ask iit jee aieee pet cbse icse state board community Community Discussion Question: So you thought you were good at numbers!
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hsbhatt (5804)

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Let S = r - 2r2 + 3r3 - 4r4+...
Sr = r2 - 2r3 + 3r4 -
 
Hence S(1+r) = r - r2 + r3 -....
 
or S(1+r)  = r/(r+1)
 
or S =  r/(r+1)
 
Now taking limit as r1, we get
r1 S = 1/4
 
Also r1 S = r1 r - 2r2 + 3r3 - 4r4+... = 1 - 2 + 3 - 4 + ....
 
Now 1 - 2 + 3 - 4 + .... = (1+2+3+4+...) - 2(2+4+6+8+...)
                                 = (1+2+3+4+...) - 4(1+2+3+4+...)
                                 = -3(1+2+3+4+...)
 
Hence 1+2+3+4+... = -1/12.
 
What's going on here?!!!!!

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apurviitjee2008 (1414)

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well this is just an attempt but i think the case goes wrong in the second step where s is multiplied with r especially for the case when r 1
it can also be multiplied with r^2 and in that case a different result is obtained
just an attempt
plz correct me if i m wrong
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hsbhatt (5804)

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But is anyhting wrong with what is done above?

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apurviitjee2008 (1414)

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Sir i meant that u will get many solns in that case (inwhich s is multiplied with r and r tends to 1)
it can also be multiplied with r ^2 or r^3 etc
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hsbhatt (5804)

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Hey wait, what did you get by multiplying with r2?
 
 I checked with r3, you get the same result.
 
It comes back to what is going on here?

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Sir it comes something like this
S(1+r2)=r-2r2+3r3-4r4+.........
this is an AGP sequence
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hsbhatt (5804)

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Just check your working, I don't think you will be able to evaluate the limit when you mutilpy by r2. I mean if you try S(1-r2), you will get a geometric sum, with no limit when r tends to 1.
 
If you multiply by r3 and in general odd powers of r, you will get the limit as 1/4. So no probs about the value of the limit

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yes Sir thats what i m also getting
unable to evalute the limit when multiplied with r^2
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Sir then the result does come out to be different for r^2
i think there lies the hint
the limit comes as 1/4 only for odd powers of r
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hsbhatt (5804)

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anyone with any inputs on this one?

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sboosy (3065)

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yes bhattji ..but pls correct me if wrong
actually u have used that
r-r^2+r^3 ...= r/r+1
but sum of infinite series only can b written like that
and for that r<1 and secondly there is some ambiguity
with 1-2+3 ... as it cud b positive for odd n
anyway that i think is not a problem except that r /r+1
i think is not right
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hsbhatt (5804)

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Actually, this is a famous result by a great mathematician. And an accepted result. But it made no sense to me. Apparently it does to a lot of guys. I wanted to see your reactions to it.
 
 
sboosy i compared the limit of two equivalent expressions when r tends to 1. I didnt equate them for r=1.

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neeraj_agarwal_1990 (887)

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sboosy (3065)

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My point is sir ..how in the first place u got r-r^2+r^3...as r/r+1
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