|
|
|
|
|
| Author |
Message |
![[Post New]](/templates/default/images/icon_minipost_new.gif) 22 Apr 2007 22:23:26 IST
|
|
|
If f(x)=[x} g(x)=sin  x , 0  x 2 . Find (g.f)(x)? |
|
|
|
23 Apr 2007 11:31:50 IST
|
|
|
Dear,
f(x)=[x]
g{f(x)} =sin  {f(x)} , 0 f(x) 2
g{f(x)} =sin {[x]} , 0 [x] 2
so [x] can be 0 ,1, 2 only .
g{f(x)} =sin (0) , 0 x < 1
= sin (1) , 1 x < 2
= sin (2) , 2 x < 3
g{f(x)} = 0 , 0 x < 1
= 0 , 1 x < 2
= 0 , 2 x < 3
g{f(x)} = 0 , 0 x < 3
|
this reply: 10 points
(with 2 
in 2 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
|
|
|
|
|
|
|
Moderation Team
![[Up]](/templates/default/images/icon_up.gif "[Up]"){kind=icon}
