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![[Post New]](/templates/default/images/icon_minipost_new.gif) 28 Jun 2007 01:21:42 IST
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Please see the image
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hey
Answer=n-1 because (sinx/x) very near to one when x-->0 so
(nsinx/x) will be very near to n from left side for both side limit
so greatest integer will be (n-1)
cheers :)
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 28 Jun 2007 12:29:37 IST
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the ans shud be n itself since v can take n out frm de gr8st int func as n is a natural no.....and limsinx/x as x->0 is 1........
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MaNuTd RoXxXx..MaNuTd 2 WiN PrEmIeR LeAgUe ThIs SeAsOn ToO AlOnG WiTh ChAmPiOnS LeAgUe.....HaiL RoNaLdO ...HaiL LaMpArD... |
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 28 Jun 2007 13:02:31 IST
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i think limit does not exist at tht point ...... bcoz ...when we go frm 0 negative sinx/x will be greater thn 1 as sinx>x when x<0................. therefore the function wud f(x) >=n. becoz of [ ]
and when we go frm 0 positive sinx/x will be less than one as x > sinx when x>0 there fore f(x) < n bcoz of [ ] LHL CAN NEVER BE EQUAL TO RHL so since LHS limit not equal to RHS limit limit doesnot exist
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What i wud lyk to be is unique....Govind |
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 28 Jun 2007 13:09:50 IST
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aare yaar! c sinx/x<1 it tends to 1,its value is 0.9999...... n*0.9999 is less than n lies b/w n-1 & n hence d ans is n-1. plz rate me if d ans is correct!!
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 28 Jun 2007 13:13:07 IST
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karthik2789 u r ryt abt tht .....but x also tends frm right side.....so it can be 1.0000000000000000000001 also.....then the value is greater thn n so LHL is not equal to RHL
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What i wud lyk to be is unique....Govind |
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 28 Jun 2007 13:47:52 IST
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i think the limit does not exist
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 28 Jun 2007 14:46:47 IST
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hey limit exist very much .. plz dont put wrong answer sinx/x never be greater than one either u approach from left or right :)
remember lim(x--.0)(sinx/x) always near to one from left side it never be equal to one or greater than one
Its limiting value is one not EXACT value
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 30 Jun 2007 00:12:34 IST
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@ iit_2008_yr yaar the question is greatest integer function so when sinx/x is less than 1 , [ ] becomes 0 and when greater thn 1 it becomes 1....and sinx/x does become greater thn 1
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What i wud lyk to be is unique....Govind |
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 2 Jul 2007 18:44:20 IST
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 11 Jul 2007 23:22:46 IST
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the limit does exists and the answer is n-1,for sure!!!!! from the graph,we get sin xsinx/x<1 n sinx/x[n sin x/x]=n-1 please rate if satisfied!!!!!!!!!!!!!!
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<TABLE CELLSPACING="1" CELLPADDING="1" BORDER="0">
<TR><TD>
   
<DIV ALIGN="right">Animated Letters</DIV></TD></TR></TABLE>
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 11 Jul 2007 23:35:18 IST
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u can't take "n" out of[ ]! u can take it out if it is in addition.....
So answer is n-1...as explained by others...
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