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![[Post New]](/templates/default/images/icon_minipost_new.gif) 8 Apr 2008 22:25:32 IST
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[x ] [0 ] (sinx/x)sinx/(x-sinx)
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"Only two things are infinite, the universe and human stupidity, and I'm not sure about the former." --Albert Einstein |
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8 Apr 2008 22:28:19 IST
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L = lim x-> 0 [ 1 + (sinx - x /x) ]^(sinx/x-sinx) = e^-1 = 1/e
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8 Apr 2008 22:28:31 IST
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e to the power -1 i.e 1/e
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_________________________
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8 Apr 2008 22:32:21 IST
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can u please give me the method also
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8 Apr 2008 22:37:58 IST
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l =  l =  l =  l =  method already given by sandeepramesh..... i just latexified it...... hope you are clear.........
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8 Apr 2008 22:44:13 IST
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ya
thanks
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