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![[Post New]](/templates/default/images/icon_minipost_new.gif) 19 Nov 2007 20:17:36 IST
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x+x+x+x+x+x+x+x+x................................x times = x2 differentiatin both sides wrt x 1 + 1+1+1+1+1+1+1............................x times = 2x => x = 2x cancellin x 1 = 2 spot the defect in d workin..................... 
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 19 Nov 2007 20:23:47 IST
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u have ignored x=0 as the solution
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 19 Nov 2007 20:25:00 IST
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dats jus 1 case u can make out try out other cases it comes out 1=2 try again 
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 19 Nov 2007 20:37:04 IST
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nobody tryin!!! hey brainys buck up!!!
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x+x+x+x....x times = x^2 only when x is an integer...so x becomes a non differentiable function
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 19 Nov 2007 20:45:33 IST
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wow joy excellently answered  ya dis fn isnt continuous n wont hold for fractional values so dis bcums a non differentiable fn............ well done n ya if u liked d question plzzz rate me for it............................. cheers
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 19 Nov 2007 20:46:23 IST
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hey ishita, this is such a disgusting sort of mathematics
saying if 1*0=0 and 2*0 = 0 then 1=2.
if u have an equn, 2x-2=0 or x=1 u could well have said 3x-x-3+1=0 of 3(x-1)=x-1 so either x=1 or 1=3. but looking up, the eqn was as simple as x-1=0 or x=1
was'nt that what u were mistaking
the only soln to ur eqn 2x=x is x=0. one more thing, it is a linear eqn, it can't have more than 1 root
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 19 Nov 2007 20:49:59 IST
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what is so disgusting?...conceptual problems are good..
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 19 Nov 2007 20:51:44 IST
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wrong dis question was asked in one of d competitive exams in d mains n d answer joy gave is d perfect soln to it d ques itself said find d defect so obviously it had 2 b wrong na n if u thnk it was disgustin u might as well believe d same for d exam it wasnt made up by me but ya d answer was found out by me............. dats why i posted it here 2 make others also aware of d trick dont u thnk i deserved a better reply dan wat u gave???
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 19 Nov 2007 20:52:28 IST
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aaye joy!!! mujhe bhi fiitjee sir ne yahi puccha tha... !! u too?! well differentiation is only applicable for continuous small values and not discreet values like integers which exist at specific points. Hence the working is invalid.
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 19 Nov 2007 20:53:08 IST
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ya dats rght!!!!
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 19 Nov 2007 21:02:14 IST
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the important thing in the question was to say the non differentiability of the function which is correct.nothing disgusting in that.
the point i was pointing was that saying there r two solutions of the eqn 2x=x, 0 and something else is absurd. i meant if x=2x, it doesn't mean that 1=2
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<TABLE CELLSPACING="1" CELLPADDING="1" BORDER="0">
<TR><TD>
<DIV ALIGN="right">Animated Letters</DIV></TD></TR></TABLE>
I am only one,
But still I am one.
I cannot do everything,
But still I can do something;
And because I cannot do everything
I will not refuse to do the something that I can do.
- Edward Everett Hale
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 19 Nov 2007 22:09:31 IST
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dat ws a gud one
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 19 Nov 2007 22:19:33 IST
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gud one takes u right to the basics :)
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 20 Nov 2007 11:49:45 IST
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