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Differential Calculus
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12 Sep 2007 03:38:48 IST
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The Derivatives of Higher Order of tan x
Discovery Process:
The first five successive derivatives of the function f(x) = tan x may be discovered by entering this single line in Derive:
d tan x/ dx = 1+tan2x
d2 tan x /dx2 = 2tan x + 2tan3x
d3 tan x /dx3 = 2+ 8tan2x + 6tan4x
d4 tan x /dx4 = 16tan x + 40tan3x+24tan5x
d5 tan x /dx5 = 16+ 136tan2x + 240tan4x+120tan6x
Observation:
(1) The successive derivatives of f(x) are polynomials of tan x. A closer examination suggests that the n-th order derivative of f(x) is of the form pn+1(tan x), where pn is a polynomial of degree n.
(2) Arranging the coefficients in the tabular each entry is seen as a sum of the upper left-hand and the upper right- hand entries multiplied by the respective column numbers.
Reconstruction:
The coefficients of the polynomials pn may be reconstructed by means of a spreadsheet. After the entry 1 indicating the obvious identity tan x = tan x is placed, there is only one formula to be entered and then copied: The reconstruction is based on the formula
dn tan x /dxn = ntann-1x + ntann+1x,
from which the recurrence relation of the polynomial sequence {pn(z)}
p1(z) = z, pn+1(z) = p'n(z)(1+z2), n ³ 1 is then formulated.













y=sinx/cosx then cross multiply and differentiate n times
both sides.