To, Mr. Kavincoollz,

 

1 + 1 + 1 + 1 (4times) = 4 x 1 = 4

 

Observe, 2 + 2 +2 + 2 (4times) = 4 x 2 = 8

 

Now , 3 + 3 + 3 (3 times) = 3 x 3 = 3^2 = 9

 

So, x + x + x + x ...... ( x times ) = x.x = x^2

 

There is nothing wrong in this step

My dear friend... in ur given equation

X+X+X+X......   X times

the no.of times a no. X is summed must be a constant therefore for the below equation ....

X+X+X+X+.......   X' times  where X'=X  we have X' as constant....

So,

X+X+X+X......   X' times = X*X'

Differentiating  both sides

1+1+1+1+......X'  times = X'   AS X' IS COMMON...

 

 

In the problem we can only sum up x like that if and only iff x belongs to the set of positive integers & not otherwise. Under this conditions, x is not a variable.

Hey ariyam66,

 

U hav assumed here that X is not equal to 0. Then instead of putting X , write that particular number corresponding number of times and RHS will be number square .Differentiate and u will get 0=0 . Or Just tell me a number that u will write so many times and get what i say . U cant. The very quantity changes when u differentiate and equality wont hold good.

                            

                                        cos=0

 

solving one value of  = /2

 

If u differentiate the above eqn u get one value sin= 0 ie  is 0. But we got  value which doesnt match with this. So by differentiating an eqn, u wont get the same roots.In fact u will get (the sum of the roots)/2 . Try it

 

Now u get it . One word to titun, hey titun u r signature  2nd line is not that cool.