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Differential Calculus

Blazing goIITian

Joined:	12 Apr 2008
Post:	424

30 Sep 2009 12:05:27 IST

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find shortest dist. b/w curve x^2 + y^2 =4 nd pt. (6,8)

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VINEET KUMAR

Cool goIITian

Joined: 25 Aug 2009

Posts: 69

30 Sep 2009 12:16:42 IST

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ans is 8unit

zzzzz

Blazing goIITian

Joined: 12 Apr 2008

Posts: 424

30 Sep 2009 12:17:27 IST

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yeah.........but how did u got this?

Vijay Pal

Forum Expert

Joined: 1 Jun 2009

Posts: 2305

30 Sep 2009 12:22:54 IST

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lets see this is the equation of a circle having centre (0,0) ie origin and radius 2 unit.now the distance of (6,8) from its centre is =10 unit

so the shortest distance of point will be 10-radius =10-2 =8 unit

VINEET KUMAR

Cool goIITian

Joined: 25 Aug 2009

Posts: 69

30 Sep 2009 12:26:28 IST

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simple

the eqn is of a circle ok with centr (0,0)

now any line passing through (6,8) shold be normal to the circle which again passes through the center must cut it at 2 points

now we can calculate the distance of 6,8 and origin we will get 10 unit and the radius of circle is 2 unit so max distance will be 10+2

and minimum distance will be 10-2 =8unit

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