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Differential Calculus

akhil's Avatar
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3 Apr 2009 10:04:17 IST
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best questions ever......on functions
None

Letf(x) =min{ x-[x] ,  -x-[x]}, -2<=x<=2 ;

 

g(x)=|2-|x-2|| ,-2<=x<=2

 

and h(x)=|sin x|/sinx,-2<=x<=2

 

and x not = 0.

 

on the basis of above information....

 

 

1)the no. of solution of the eqn..x2+[f(x)]2=1 is....{-1<=x<=1}

 

a)0   b)2  c)4  d)6

 

 

2) the rabge of f(x) ...

 

a) [0,0.5]  b) [0,1]   c)[0,2]  d)none of these.

 

 

3) the sum of all the roots of the eqn g(x)-h(x)=0 is..{-2<=x<=2}

 

a)+ve   b)  -ve  c)0   d)none of these..

 

 

4) The set of values of a such that eqn f(x)-a=0

 

a) a belongs to (0,0.5)

b)a belongs [0,0.5)

c)a belongs [0,1]

d) a belongs (0,1)

 

 

5) the value of integration of f(x)dx..{with limit -2 to 2} is

 

a)0  b)  1  c) 2  d) 8

 

 

HELP ME!

RATES ASSURED!

GIVE SOLUTIONS OR HINTS!


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Comments (17)

pranav agrawal's Avatar

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3 Apr 2009 10:07:45 IST
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is it the greatest integer function [f(x)] in question 1 ? ?
akhil's Avatar

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3 Apr 2009 10:10:29 IST
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NO!!!!!!!!

pranav agrawal's Avatar

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3 Apr 2009 10:44:21 IST
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??

Decoder's Avatar

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3 Apr 2009 10:52:32 IST
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1) ...2...use graphs..2) [0,1/2]...3) +ve (1,1) actually...4) same like 2)....only for a=0.5...it will give 4 solutions...5) 1..... as area under f(x) on one period is 1/4....now it is swept over four periods ....(-2,2)
saharsha kumar keshkar's Avatar

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3 Apr 2009 10:54:35 IST
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(2)

clearly the range is [0,1/2]

hence option (a) is correct....

pranav agrawal's Avatar

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3 Apr 2009 11:01:53 IST
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will u pls plot the graph~~
saharsha kumar keshkar's Avatar

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3 Apr 2009 11:03:48 IST
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pranav agrawal's Avatar

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3 Apr 2009 11:05:20 IST
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i m asking of y=f(x)~
saharsha kumar keshkar's Avatar

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3 Apr 2009 11:10:16 IST
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saharsha kumar keshkar's Avatar

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3 Apr 2009 11:18:52 IST
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akshay A NEW BEGINNING...'s Avatar

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3 Apr 2009 11:19:34 IST
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here are my answers through graph..

1 b

2 a

3 a 

4 b

5 b

plss tell me how to post the grpah...

saharsha kumar keshkar's Avatar

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3 Apr 2009 11:32:40 IST
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saharsha kumar keshkar's Avatar

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3 Apr 2009 11:34:02 IST
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hence my answers are......

b)

a)

a)

a)

b)

not sure abt first question....

saharsha kumar keshkar's Avatar

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3 Apr 2009 11:51:42 IST
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@ akshay i think ur 4th answer is wrong....

please check...i m also checking my answers...

akhil's Avatar

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3 Apr 2009 12:40:49 IST
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rates to ALL who posted answers to my question....... ans given in my boofk are:

b)

a)

a)

a)

b)

 

AGAIN THANKS TO PRANAV ,SAHARSHA,AKSHAY.......and every one

akhil's Avatar

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3 Apr 2009 12:41:41 IST
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oh yes DECODER also...very much thanx to u....

radhika's Avatar

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3 Apr 2009 19:03:21 IST
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good...questions...




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