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Differential Calculus

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4 Apr 2009 13:54:54 IST

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402

continuity and differentiability.

None

assertion: f(x)is continious ,then |f(|x|)| is also continious.

reason: if |f(x)|<= |x|( where x belongs to R), then |f(x)| is continious at x=0.

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A$PIRing HiGh - dEv aDitYa

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Joined: 13 Mar 2008

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4 Apr 2009 14:11:00 IST

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I think both A and R are correct but R is not right xplanation of A. Not completely sure. I wrong, please let me know

saharsha kumar keshkar

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Joined: 7 Aug 2008

Posts: 1104

4 Apr 2009 14:25:33 IST

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agree with @ aspire for more....

similar type problem was discussed in our class........

saharsha kumar keshkar

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4 Apr 2009 14:27:42 IST

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radhika

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4 Apr 2009 16:33:17 IST

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thax a lot!

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