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Vertical Limit
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hello,
since function is continious at x=2
hence at x=2 l.h.l.=r.h.l=b
for r.h.l. limx--->-2 x4-16/x5+35 = 4x3/5x4=4/5x=-2/5 (applying L'obtal rule and differenciating)
hence sin x4-16/x5+35 =sin(-2/5)
so b=sin(-2/5)
now for l.h.l. clearly e1/
= infinity as x->-2 hence divide numenator and denomenator e1/
and applying limit we get l.h.l.=-a
-a=b hence a=sin2/5