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Differential Calculus

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3 Jan 2012 20:23:56 IST

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Diffrentiate the value sec^(-1) [1/2x^(2)-1] with respect to 1/[whole root] 1-x^(2) where x=1/2.

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ROHAN KUMAR

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Joined: 1 Jan 2012

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14 Jan 2012 19:33:47 IST

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Take F(x)=sec^(-1)[1/2x^2 -1] and f(x)=1/[whole root]1-x^2 Then find F?(x) and f?(x) .then divide F?(x) from f?(x) and put x=1/2 to get the answer

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