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Differential Calculus

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14 Nov 2011 18:39:53 IST

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Mathematics

domain of f(x)= ((1/sinx)-1)^1/2 is

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Rajdeep chakraborty

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Joined: 17 Aug 2009

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20 Nov 2011 16:20:43 IST

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f(x)=(1/sinx -1)^1/2

domain of f(x) is given by: (1/sinx -1) > 0 and sinx not = 0

ie, 0 < sinx <= 1

or, 2nπ < x < (2n+1)π

ie, x ? (2nπ , (2n+1)π)

Manasi

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Joined: 1 Dec 2006

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11 Feb 2012 12:30:27 IST

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the question is already solved :)

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