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Differential Calculus

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16 Aug 2009 12:07:43 IST

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f(ax) = f(x) / a; where f(x)>=0 Prove that the solution of f(x) = k/x is unique

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f(ax) = f(x) / a; where f(x)>=0Prove that the solution of f(x) = k/x is unique

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Yagyadutt Mishra

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17 Aug 2009 19:09:26 IST

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Yagyadutt Mishra

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Posts: 1984

17 Aug 2009 19:09:47 IST

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Yagyadutt Mishra

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Posts: 1984

17 Aug 2009 19:10:05 IST

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Yagyadutt Mishra

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17 Aug 2009 19:24:33 IST

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One thing more graph will be only in first quadrant coz...f(x) is postive onl..hence...in my last post ignore the graph of f(x) in third quadrant..

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