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Differential Calculus

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11 May 2010 05:06:31 IST

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f(x) = Ix-1I + Ix-2I ,

None

f(x) = Ix-1I + Ix-2I ,-1<_x<_3

Find the range

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R Lokaditya

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Joined: 14 Mar 2009

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11 May 2010 09:14:07 IST

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range [1,5]

Deepak Aggarwal

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Joined: 9 May 2009

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11 May 2010 19:21:24 IST

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f(x) = |x - 1| + |x - 2|

= 2x - 3 , x > 2

1 , 1 < x < 2

- 2x + 3 , x < 1

Clearly, range of f(x) is [1,5].

Yagyadutt Mishra

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Joined: 19 Feb 2009

Posts: 1984

11 May 2010 19:32:02 IST

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f(x) = |x - 1| + | x-2|

(-1) ---------------------(1)--------------------(2)-------------------(3)

-X+1-(X-2) X-1-X+2 X-1+X-2

F(X)=-2X+3 F(X) =1 F(X)=2X-3

DECREASING CONSTANT INCREASING

SO MAX = 5 SO MAX AND MAX = 6-3 = 3

MIN =1 MIN BOTH = 1 MIN = 1

CONSIDERING WHOLE DOMAIN WE ARE GETTING MAXIMUM AS 5 AND MINIMUM AS 1...

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