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Differential Calculus

Cool goIITian

Joined:	13 Feb 2009
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5 Mar 2010 12:12:33 IST

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Hello ..can sm 1 ans this---- if a Function f:R----R is defined by f(x)=x !x! ..(ie is modulus) x i

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Hello ..can sm 1 ans this---- if a Function f:R----R is defined by f(x)=x !x! ..(ie is modulus) x is real then find f ' (0) - f ' (1).............options 2,-2,0,-1

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Yagyadutt Mishra

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Joined: 19 Feb 2009

Posts: 1983

5 Mar 2010 13:15:06 IST

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f(x) = x|x|

For x>0 f(x) = x^2

f'(x) = 2x

f'(1) = 2 because 1>0

and similarly at x=0 function has two values....of f'(x)

f'(x) = -2x ;x<0

f'(x) = 2x ; x>0

but x=0 both will give 0

f'(0) -f'(1) = 0 -2 = -2 ans

spidy

Cool goIITian

Joined: 13 Feb 2009

Posts: 43

5 Mar 2010 14:53:54 IST

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oops i made a mitk its actually f'(0) - f'(-1) ...but nyway we get the same ans ie -2 ...thanks for the method !!

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