If a and b are two fixed positive integers such that f (a + x) = b + [b3 + 1-3b2 (f (x) + 3b(f (x))2
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If a and b are two fixed positive integers such that f (a + x) = b + [b3 + 1-3b2 (f (x) + 3b(f (x))2-(f (x))3]1/3 for all real x then f (x) is periodic function with period
Now replace x by x+a :
from (1) and (2) :
so f is periodic with period 2a