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Differential Calculus

Blazing goIITian

Joined:	9 Mar 2008
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18 Mar 2010 22:50:59 IST

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if f(x)=2 then domain of f(x) is REAL NUMBERS. but if we write f(x)=2x^0 then x cannot be equal to

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if f(x)=2then domain of f(x) is REAL NUMBERS.but if we write f(x)=2x^0 then x cannot be equal to zero.because 0^0 is not defined.then domain should be R-0. ie graph should be discontinue at 0. where is the problem

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Missionadmission

Blazing goIITian

Joined: 8 Oct 2008

Posts: 1252

19 Mar 2010 00:49:00 IST

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If I remember corectly 0*0 is not undefined.. Its only undefined when one of the zeros is a number close to zero but not actually zero.

Even the calculator that comes with windows computes 0*0 to be o

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Blazing goIITian

Joined: 11 Apr 2009

Posts: 672

19 Mar 2010 02:32:34 IST

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dats because you are putting the wrong value...the domain is R ....and yes 0*0 is 0......@ aditya nice observation abt dat windows calculator!

Krishna Gopal Singh

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Joined: 29 Dec 2006

Posts: 4965

19 Mar 2010 09:16:46 IST

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aditya Ayush is asking about 0^0 and not 0*0 and windows calculator gives 0^0 = 1.Ayush they are different functions and they will have diffrent domains. Lets see it with another example. If f(x) = 2 and g(x) = (2x-6)/(x-3) then f(x) = g(x) for all x other than 2. So domain of f(x) is R while that of g(x) is R-{3}.So i do not see any problem in having different domains for different functions.

ayush

Blazing goIITian

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19 Mar 2010 20:21:39 IST

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thanks krishna sir

but sir is it wrong to write 2=2x^0 x is not zero. if true then how to dRAW graph at x=0

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