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Differential Calculus
FIND DOMAIN!
i think only one condition is there
2 - |x| / 4 <=1 and 2- |x| / 4 >=-1
for 2 - |x| < 4
|x| > -2
hence x belongs to R
and
2 - |x| >= -4
|x| <= 6
hence x belongs to [-6,6]..
let y= f1(x) + f2 (x) +f3(x)
f1(x) is defined...
-1<= {(2-|x|)/4}<=1
0<=|x|<+6
or Domain of f1 is [-6,6]
similarly domain of f2 is also [-6,6]
and domain of f3(x)=R
hence .D1 intersection D2 intersection D3 gives us...
D=[-6,6]
in all the three addends, only one condition is applicable.
rate, if helpful.
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i think only one condition is there
2 - |x| / 4 <=1 and 2- |x| / 4 >=-1
for 2 - |x| < 4
|x| > -2
hence x belongs to R
and
2 - |x| >= -4
|x| <= 6
hence x belongs to [-6,6]..