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Differential Calculus

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22 Dec 2011 11:17:25 IST

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lim x-tends to 0,rout uder 1-x-rout under 1+x/x

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lim x-tends to 0,rout uder 1-x-rout under 1+x/x

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Arjun Virmani

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Joined: 1 Jun 2009

Posts: 1294

26 Dec 2011 21:12:43 IST

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If its √(1-x) - √(1+x) / x......

then at x-- 0.

its 0 / 0

apply L'hospital rule.

differentiate num and den. separately!!

u'll get [1/2 * -1 / √(1-x)] - [ 1/2 * 1 / √(1+x) ].

now put x =0...........

u'll get -1/2 - 1/2 = -1 !!!!

ROHAN KUMAR

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Joined: 1 Jan 2012

Posts: 143

5 Jan 2012 08:14:47 IST

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You can solve it by multiplying and dividing it with underroot 1-x + underrout 1+x then simplify it and then put the x=0

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