draw a trapezium ABCD with AB parallel CD and AB=BC=AD=6cm with CD>AB . let DE=FC=x .then AE=BF=square root(36-x square) .area of trapezium is (x+6)*square root(36-x suare).differentiate and equate to 0 and get x=2.so CD=10cm. so the trapezium has maximum area when the fourth side is 10 cm long .
draw a trapezium ABCD with AB parallel CD and AB=BC=AD=6cm with CD>AB . let DE=FC=x .then AE=BF=square root(36-x square) .area of trapezium is (x+6)*square root(36-x suare).differentiate and equate to 0 and get x=2.so CD=10cm. so the trapezium has maximum area when the fourth side is 10 cm long .