Home » Ask & Discuss » Mathematics. » Differential Calculus « Back to Discussion

Differential Calculus

djdylan2000. bits goa eee

Blazing goIITian

Joined:	7 Feb 2007
Post:	1608

23 Mar 2009 14:24:07 IST

0 People liked this

274

Minimum Area

None

Find the equation of the line passing through (3,4) and making a triangle with co-ordinate axes with minimum area, in the 1st quadrant.

Share this article on:

Comments (3)

pink_ele

Blazing goIITian

Joined: 16 Jan 2007

Posts: 1836

23 Mar 2009 14:33:05 IST

Like 1 people liked this

let line be x/a+y/b=1.....this gives...3/a+4/b=1......===>a=3b/(b-4)...area=1.2ab=3b^2/2(b-4)....diffrentiating and eqting to zero we get....b=8....so a=6line is 4x+3y-24=0

A$PIRing HiGh - dEv aDitYa

Blazing goIITian

Joined: 13 Mar 2008

Posts: 540

23 Mar 2009 14:35:44 IST

Like 0 people liked this

is the ans 4x-3y =12

Madmax

Blazing goIITian

Joined: 24 Dec 2007

Posts: 1111

24 Mar 2009 00:35:31 IST

Like 0 people liked this

@A$PIRE for MORE 4x-3y =12 doesn't pass thru the given pt 3,4....The answer is indeed 4x+3y=24 ....cheers!!

Quick Reply

Reply

	Some HTML allowed.
	Keep your comments above the belt or risk having them deleted.
	Signup for a avatar to have your pictures show up by your comment
	If Members see a thread that violates the Posting Rules, bring it to the attention of the Moderator Team