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Differential Calculus

Blazing goIITian

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10 Oct 2009 23:31:15 IST

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1076

no. of critical pts. of y= max (sin x, cos x) for x £ (o , 2 pi)

None

no. of critical pts. of y= max (sin x, cos x) for x £ (o , 2 pi)

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Comments (10)

C!-!!NMAY

Blazing goIITian

Joined: 30 Mar 2008

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10 Oct 2009 23:40:50 IST

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edited :3 i think

C!-!!NMAY

Blazing goIITian

Joined: 30 Mar 2008

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10 Oct 2009 23:48:35 IST

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yeah i think its 3,,see u draw the graph of sinx and cosx simultaneously,,,and for max consider only upper line of both curve u will see points dy/dx=0 at one points and at 2 points dy/dx is not defined,,,so we get 3 points end points r not considered in critical points ,,,and hence answer is 3 critical points....

zzzzz

Blazing goIITian

Joined: 12 Apr 2008

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10 Oct 2009 23:52:17 IST

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ans. is 3 but i am getting 2

akhil kumar

Cool goIITian

Joined: 14 Apr 2007

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10 Oct 2009 23:52:39 IST

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graph of max(sinx ,cosx)

by the graphs there are 2 pts.

HeMaNt..... ThE DeViL....

Blazing goIITian

Joined: 22 Jul 2008

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10 Oct 2009 23:54:29 IST

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i think its 3

C!-!!NMAY

Blazing goIITian

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10 Oct 2009 23:55:07 IST

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okh thrre is correct i also considered starting points as critical points but starting points nahin hote critical points so 3 is correct answer and sorry for that answer

HeMaNt..... ThE DeViL....

Blazing goIITian

Joined: 22 Jul 2008

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11 Oct 2009 00:01:37 IST

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3 points marks here....

that are two critical points.

C!-!!NMAY

Blazing goIITian

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11 Oct 2009 00:03:43 IST

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see hemant there is another one point at which dy/dx of max{sinx,cosx} is zero,,,so find it mujhe dikh rahah hai tumko bhi dikhna chahiye ,,,baaki kal discuss karenge abhi gn to all,,,and hemant dhoondte raho :-)

C!-!!NMAY

Blazing goIITian

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11 Oct 2009 12:11:29 IST

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good hemant,,,,ab sahi lag raha hai ...

Bipin Dubey

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Joined: 23 Jan 2007

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11 Oct 2009 12:31:41 IST

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Good work Hemant. The figure is enough to understand the problem.

critical points are at x = pi/4, pi/2, 5pi/4

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