We just need to concentrate again on a period only let it be x belonging to 0 to 2pi
Now from x =0 to x=pi/2
everywhere sinx is less than 1 so graph would be same as sin(x) but on x=pi/2 sinx becomes 1 so every comes first point of disconcounity {sin(pi/2)}=0
again after x=pi/2 to x =pi
graph would be same as sin(x)
Then from x =pi to x=2pi ( excluding these points )
sin(x) lie b/w 0 and (-1) so its Greatest integer part would be (-1)
So just add 1 to the graph or in easier way uplift the graph to 1 unit .
Repeat the pattern further on .
Thank u
We just need to concentrate again on a period only let it be x belonging to 0 to 2pi
Now from x =0 to x=pi/2
everywhere sinx is less than 1 so graph would be same as sin(x) but on x=pi/2 sinx becomes 1 so every comes first point of disconcounity {sin(pi/2)}=0
again after x=pi/2 to x =pi
graph would be same as sin(x)
Then from x =pi to x=2pi ( excluding these points )
sin(x) lie b/w 0 and (-1) so its Greatest integer part would be (-1)
So just add 1 to the graph or in easier way uplift the graph to 1 unit .
Repeat the pattern further on .
Thank u