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Differential Calculus

Blazing goIITian

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21 Mar 2010 21:10:46 IST
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 what is the derivative of sin(x^0)


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siDDhESwaR MuKhErjEE's Avatar

Blazing goIITian

Joined: 15 Nov 2009
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21 Mar 2010 21:24:25 IST
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I guess the derivative would be 0 since the given expression is a constant


Blazing goIITian

Joined: 13 Nov 2008
Posts: 348
21 Mar 2010 21:49:13 IST
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 i am not sure but i think its not 0

HIMANSHU JAIN's Avatar

Scorching goIITian

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22 Mar 2010 17:51:14 IST
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It is zero.

look, it this way:

derivative:  Cos(x^0) multiplied by derivative of x^0.

which is zero.

I hope I am clear..

siDDhESwaR MuKhErjEE's Avatar

Blazing goIITian

Joined: 15 Nov 2009
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29 Mar 2010 20:21:33 IST
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yup it has to be zero........basically the thing is derivatives of such functions cannot be found out.
» ÆoniuM XEonAX «'s Avatar

Scorching goIITian

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29 Mar 2010 20:25:24 IST
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Derivative:


 



d/dx(sin(x^0)) = 0

 





Possible derivation:\nd/dx(sin(1))\n | The derivative of sin(1) is zero:\n= | 0

 







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