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Differential Calculus

Hot goIITian

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Post:	119

3 Apr 2009 16:31:33 IST

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300

simple--LIMITS

None

is equal to....

a)1

b)-1

c)0

d)none of these

RATES ASSURED!

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Comments (8)

A$PIRing HiGh - dEv aDitYa

Blazing goIITian

Joined: 13 Mar 2008

Posts: 540

3 Apr 2009 16:40:08 IST

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is it 1

1-cos2x=2(sinx)^2 . So it becomes root(sinx)^2 /x = sinx/x .

ar rehman

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Joined: 24 Feb 2009

Posts: 119

3 Apr 2009 16:45:18 IST

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i m also getting this but this not d answer....

saharsha kumar keshkar

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3 Apr 2009 16:46:10 IST

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hello!

it's answer is (d)................

think till i send my solution

pranav agrawal

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Posts: 1694

3 Apr 2009 16:46:20 IST

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on solving

we have, limx---> 0 |sinx| / x

now lim x---->0 - f(x) = lim h--->0 f( 0 -h)

= lim h--->0 |sin (-h) | / -h

= lim h--->0 sinh / -h

= -1

lim x---->0 + f(x) = lim h--->0 f( 0 +h)

= lim h--->0 |sin (h) | / h

= lim h--->0 sinh / h

= +1

hence

left hand limit =/ left hand limit

so,

limit does not exist~~

done~~

saharsha kumar keshkar

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3 Apr 2009 16:51:02 IST

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here,

f(x)=1-cos2x=2 sin²x

then ur ques becomes..

there fore LHL =-1 and RHL= 1

hence limit does not exsist.......

pranav agrawal

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Joined: 24 Sep 2008

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3 Apr 2009 16:51:49 IST

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i did already~

saharsha kumar keshkar

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Posts: 1104

3 Apr 2009 16:55:00 IST

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here,

f(x)=1-cos2x=2 sin²x

then ur ques becomes..

there fore LHL =-1 and RHL= 1

hence limit does not exsist.......

sorry for late solution...server was down for bit.......

ar rehman

Hot goIITian

Joined: 24 Feb 2009

Posts: 119

3 Apr 2009 16:57:18 IST

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thax...posting my second ques....wait for while..

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