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Differential Calculus

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25 Jan 2012 19:03:48 IST

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solution of the differential equation-dy/dx=3yx2(x square)/x3(x cube)+2y4(y four)

Mathematics

solution of the differential equation-dy/dx=3yx2(x square)/x3(x cube)+2y4(y four)

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Arjun Virmani

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Joined: 1 Jun 2009

Posts: 1294

28 Jan 2012 03:02:36 IST

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- dy / dx = 3yx² / x³ + 2y⁴

- dy ( x³ + 2y⁴) = 3yx²dx

-dy ( x³ ) - dy ( 2y⁴) = 3yx²dx

- dy ( 2y⁴) = dy ( x³ ) + 3yx²dx........

[By Observation]

- 2 y⁵ / 5 = x³y + c (constant of integration)

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