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Differential Calculus

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31 Dec 2011 08:20:03 IST

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Whats the limit of lim x tends to 2 (x^2-4)/(x^3-4x^2+4x)

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Whats the limit of lim x tends to 2 (x^2-4)/(x^3-4x^2+4x)

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rohit rajput

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31 Dec 2011 14:03:13 IST

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Use L-Hospital

differentiate num and den.

atlast num becomes 0 while denominator=6

=> ans=0.

ROHAN KUMAR

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2 Jan 2012 14:44:52 IST

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ans = o

a.k.pavan kumar

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2 Jan 2012 19:32:01 IST

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nope!!!!!!! ans=1/2.L-HOSPITOL'S RULE.u hafta differentiate twice....1st diff:-(2x)/[(3x^2)-(8x)+4].2nd diff:-(2)/(6x-8)......now v substitute 2....2/(12-8)=(2/4)so,ans=1/2

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