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Electricity

Blazing goIITian

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24 Jun 2010 12:37:59 IST
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A hemispherical surface of radius r is placed in a uniform electric field E in such a manner that f
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A hemispherical surface of radius r is placed in a uniform electric field E in such a manner that field is directed perpendicular to the circular plane face of the hemisphere .electric flux through the said serface is A)pie (Rsquare)E b)4pie (rsquare)E c)2pie (rsquare)E d)2pieRE


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guru govind's Avatar

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Joined: 3 Apr 2010
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24 Jun 2010 15:22:40 IST
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flux=AE

the surface area of hemispehere 2piR^2

flux=2piR^2E

ans is C

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vijay kharya's Avatar

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24 Jun 2010 15:41:14 IST
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wrong, ans is A

Blazing goIITian

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24 Jun 2010 23:50:37 IST
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WHY is a ? Explain

silent killer's Avatar

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25 Jun 2010 08:49:04 IST
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ans:A

 

ajay singh rathore's Avatar

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25 Jun 2010 09:47:07 IST
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flux entering = flux going out

so as we close the hemisphere the area becomes pie r^2

because flux is defined only for closed surface

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New kid on the Block

Joined: 26 Jan 2009
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25 Jun 2010 14:26:32 IST
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ans is a

 

coz flux=E.dS = E.s.cos(theta)

area vector is perpendicular to the surface ,angle between s and E=0 deg

so flux= E.s.(1)

=E.pie R^2

thru the surface u have asked.....




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