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![[Post New]](/templates/default/images/icon_minipost_new.gif) 9 Mar 2008 18:27:37 IST
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electric field lines are coming from left to right. now a rectangular conductor is kept in its path. negative charge is induced on the left surface(say A) and positive charge on right surface(say B) are the potentials of a and b equal . why?
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9 Mar 2008 18:42:18 IST
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hey help me yaar. i think the potential difference of external electric field and potential of induced electric field will cancel out and hence potential difference of a and b should be equal.....
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9 Mar 2008 21:09:30 IST
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potential at all points of a conductor is same....always...
see...
we can't calculate it and prove but u can see it this way....
we have to bring a charge on A and B.....and the work done is the potential.....but the work done is not only due to the rectangular conductor but also due to the original electric field...
that work is equal...
u can also say that since there's no electric field b/w the part of conductor b/w A and B(since its a conductor)......so dV/dx = 0 => V is constant with respect to A and B...
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11 Mar 2008 05:20:48 IST
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Perfect answer neeraj. The potential difference is zero as there is no electric field between them
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Krishna Gopal Singh
B.Tech Chemical Engg
IIT Delhi 2002
Currently doing PhD from IIT Delhi |
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