IIT JEE , AIEEE Forum - Physics , Electricity

bhuwanaroracorroded

what happens when plates carrying d same sign of charge of a charged cpacitors r connected to each other

pliz explain

how it is different from d case when d plates carrying d opposite charge r connected

feynmann

apply charge on a plate = - charge of the other plate connected to the first plate

and conservation of charge

bhuwanaroracorroded

here d plates (of different capacicitors) carrying same sign of charge r connectd

bhuwanaroracorroded

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phyana

if same charged plated r connected then there would be a re-distribution of charge among the plates.
initial-----capacitor1 charge =c1*v1
capacitor2 charge=c2*v2
total charge of the system=c1*v1 + c2*v2...............(1)
when similarly charged plates r connected then the potentila difference between capacitors wold be same(=V)
so..........capacitor1 charge=c1*V
capacitor2 charge=c2*V
total charge of system=(c1+c2)V..........(2)
so (1)===(2)
so V= ((c1v1) + (c2v2))/(c1+c2)
now using this value of V u can get the new charge on capacitors(c1V,c2V)
but when opp charged plates r connected then nothing paculiar happen.becaz there is no difference between the potential on the individual charges.

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