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3 May 2012 11:10:20 IST
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CAPACITORS-( hard one for me)
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Q- A solid sphere of r=a & charge q, is surrounded by conducting concentric shell of inner r=2a & outer r=3a. find loss of energy when switch connecting inner solid and inner surface of shell is closed?? do reply wid solution...
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Juhi Sharma
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Joined: 22 May 2009
Posts: 2467
3 May 2012 11:33:28 IST
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See first a capicitor of charge q and capacitance 4*pi*e(ra-rb)/ra*rb would be formed..For second case the charge would be 2*q/3 And the capacitance would be same the energy would be energy difference betwwen them.....
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9 May 2012 22:48:55 IST
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when a capacitor of capacitance c1 ,charged to a potential v1,is connected with another capacitor..capacitance.c2 and potential v2....then charge flows from one capacitor to another one till their potential become equal....if we say no energy loss its not true...energy lost by one is gained by another...but there is an energy loss due to sharing charges...i think it may appear in the form of heat....that energy loss ,,,,delta u=C1C2(V1-V2)^2/2(C1+C2) POST LIKE IF U LIKE MY ANW
9 May 2012 23:26:52 IST
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if u want derivation here it is.....common potential attained due to sharing charges V=c1v1+c2v2/c1+c2total energy before sharing charges..u1=0.5c1v1^2+0.5c2v2^2total energy after sharing....u2=0.5(c1+c2)v^2 put v=c1v1+c2v2/c1+c2 then find u2 -u1 okey now frnd
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