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Electricity
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7 Apr 2009 19:13:20 IST
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PD acrross F and D ; E and C are equal as current flow is equal for both due to symetry. So no current flows thru EC and FD.
so now
R(AB) = r
R(AFEB) = 3r
R(ADCB) = 3r.
All 3 are in parallel.
so R(eq) = ( 1/r + 1/3r + 1/3r )^(-1) = 3r/5.
so eq res = 3*r/5.














3R/5
I dunno how Anshul (post below) has gotten 5/2R.....(His logic is correct....current thru the 2 branches EC and FD is zero)