| Author |
Message |
![[Post New]](/templates/default/images/icon_minipost_new.gif) 15 May 2008 12:37:40 IST
|
|
|
a system consist a ball of radius "r" carrying spherically symmentric charge and the surrounding space filled with volume density = /r .alpha=constsnt r is the dis. from the centre of the ball .
a)find the ball's charge at which the mag of elctricfield vector is independant of r outside the ball
b)how high is the field strength? permitivity of ball and surrounding is 1
|
|
|
|
![[Post New]](/templates/default/images/icon_minipost_new.gif) 15 May 2008 12:42:28 IST
|
|
|
Charge= 
calculate E with gauss law .
|
this reply: 0 points
(with 0 
in 0 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
![[Post New]](/templates/default/images/icon_minipost_new.gif) 15 May 2008 12:44:24 IST
|
|
|
hey i m not getting ur question
is the surrounding space filled with charge?
|
this reply: 5 points
(with 1 
in 1 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
![[Post New]](/templates/default/images/icon_minipost_new.gif) 15 May 2008 13:53:54 IST
|
|
|
YES SNEHA IS IT THE VOLUME CHARGE DENSITY OF THE SURROUNDING MEDIUM???
|
this reply: 0 points
(with 0 
in 0 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
![[Post New]](/templates/default/images/icon_minipost_new.gif) 16 May 2008 08:50:57 IST
|
|
|
I THINK THE ANSWER THT IS THE CHARGE ON THE SPHERE SHOULD BE

plz... rate if answer is correct. u can ask further if u require the solution.
|
this reply: 0 points
(with 0 
in 0 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
![[Post New]](/templates/default/images/icon_minipost_new.gif) 16 May 2008 09:53:37 IST
|
|
|
indrajeet sir plz tell the soln.
|
this reply: 5 points
(with 1 
in 1 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
![[Post New]](/templates/default/images/icon_minipost_new.gif) 16 May 2008 10:06:18 IST
|
|
|
spere has a radius "R"..r is the distance from the center.....this question is in iridov
|
this reply: 0 points
(with 0 
in 0 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
![[Post New]](/templates/default/images/icon_minipost_new.gif) 16 May 2008 10:07:06 IST
|
|
|
idrajeet can u explain your solution
|
this reply: 0 points
(with 0 
in 0 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
|
|
|
|
@sneha
ok now i got the question right.
I THINK NOW I HAVE TO CHANGE THE ANSWER AND PUT A SOLUTION.
TO CALCULATE THE ELECTRIC FIELD AT A POINT OUTSIDE THE SPHERE, DRAW A GAUSSIAN SURFACE THT IS A SPHERE OF RADIUS r THROUGH THE POINT.NOW INSIDE THIS GAUSSIAN SURFACE, THE TOTAL CHARGE WILL BE DUE TO CHARGE ON THE SPHERE WHICH IS LET US ASSUME Q AND OTHER DUE TO THE CHARGED MEDIUM. THE CHARGE DUE TO THE MEDIUM CAN BE CALCULATED AS BELOW.
let us assume a point at a distance r through which there is a sphere of width dr.
now charge dq will be


)
now, )
 %2B Q)
solving this for E we will get
)
now for electric field to be free from r the second expression inside the brackets must be equal to zero.

or, 
i think this is the required charge on the sphere.
hope u understood the solution.
PLZ... VOTE IF SATISFIED WITH THE SOLUTION.
|
this reply: 0 points
(with 0 
in 0 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
![[Post New]](/templates/default/images/icon_minipost_new.gif) 16 May 2008 15:07:42 IST
|
|
|
risin is right..
|
this reply: 0 points
(with 0 
in 0 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
|
|