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![[Post New]](/templates/default/images/icon_minipost_new.gif) 27 Jul 2007 13:18:17 IST
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A particle of charge q of mass m is fixed at the origin.
Another identical particle starts from the point (a,o) with speed of light at t=0;
Find force of attraction between the particles after a time t
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27 Jul 2007 17:22:56 IST
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after time t separation btw the particles is ct
where c=speed of light
as one particle is stationary so magnetic force between the 2 particles=0
the only force acting will be the electrostatic force
F=q2/4pi 0(a2+c2t2)
as the charges are identical so force of attraction=>F = -q2/4pi0(a2+c2t2)
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~ANSHUMAN
I was born intellegent, education ruined me. |
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27 Jul 2007 18:39:15 IST
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i wonder if we can apply the equation of force when 1 charge is not at rest
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28 Jul 2007 01:52:07 IST
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what is direction of motion of second particle.
As electrical force is more than gravitational force and it is repulsive for identical particles how can we have force of attraction
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Krishna Gopal Singh
B.Tech Chemical Engg
IIT Delhi 2002
Currently doing PhD from IIT Delhi |
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28 Jul 2007 07:58:02 IST
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even if the eq is valid 4 moving charges itz never the case wen v is c...never not even in my wiidest dream.ther so many factors.ahe mass of particle becomes infinite so infinite gravity??????????????think abt it nd plz.rate me
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29 Jul 2007 15:12:33 IST
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I think that motion of the particle wud depend on distance moved...
if the initial velocity is c , then a deceleration wud take place....
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