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Electricity

Bhaskar Tetarbe's Avatar
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Joined: 15 Jul 2007
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9 Mar 2009 13:09:13 IST
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Circuit question
None

In the circuit shown, each resistances is . The potential V1 as indicated in the circuit, is equal to :

a) 11 V              b) -11V                  c) 9V                  d) -9V

 


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Bhaskar Tetarbe's Avatar

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Joined: 15 Jul 2007
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9 Mar 2009 13:25:34 IST
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Someone try plzz.
Anirudh  Acharya's Avatar

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Joined: 1 May 2008
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9 Mar 2009 13:42:08 IST
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-9 volts

see current in the circuit is  1 amp

now apply kvl from V1 to ground and get the ans.

Bhaskar Tetarbe's Avatar

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9 Mar 2009 19:46:36 IST
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Well the answer given is correct.Can you elaborate this ? I did not get KVL from V1 to ground thing.I mean how can u do it when its not forming a loop.
Anirudh  Acharya's Avatar

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Joined: 1 May 2008
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13 Mar 2009 11:58:35 IST
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kvl means apply a voltage path indicated and make voltage difference equal to v1(which is of rest of the circuit)



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