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![[Post New]](/templates/default/images/icon_minipost_new.gif) 15 Jun 2008 16:26:17 IST
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a thin metal plate P is inserted between the plates of a parallel plate capacitor of capacity C in such a way that its edges touch the two plates.the capacity now becomes:
(a) C/2
(b) 2C
(c) zero
(d) infinite
answer is (d)
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there are numerous options besides I.I.T
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It has to be infinite.
When U have connected the 2 plates by a conductor, it gets converted into a pure conductor now.
Means now effectively there is no region of insulation between the 2 plates. Hence D=0 in the formula for capacitance, C=(epsilon)A/D.
So, C=infinity.
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15 Jun 2008 16:37:52 IST
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sorry for asking such a stupid question
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there are numerous options besides I.I.T
<TABLE CELLSPACING="1" CELLPADDING="1" BORDER="0">
<TR><TD>
<DIV ALIGN="right">Glitter Graphics</DIV></TD></TR></TABLE>
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15 Jun 2008 16:39:01 IST
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as it's a metal plate(conductor)....and it touches those edges...so.....net charge now on capacitor is 0
so it's no more a capacitor now.....so capacity becomes infinite
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Who says nothing is impossible.
I've been doing nothing for years !!..............
I know KUNG FU KARATE
and 47 other dangerous words.............
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15 Jun 2008 16:39:32 IST
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Also, when u connect both the plates with a conductor, the potential on both plates becomes equal as potential remains constant in a conductor.
So, it means that potential difference=0.
And Q=CV or C=Q/V.
As V=0, so C=infinity. :D
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The quality of a person's life is in direct proportion to their commitment to excellence, regardless of their chosen field of endeavor.
It is during our darkest moments that we must focus to see the light.
Check out my blog at:
http://tarinbansal.blogspot.com/
Posts:
Can marks really judge a student??
Some myths about Chemical Engineering.
(A must see for every student)
Back to goiit, this time with Baby Veerappan. :D |
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