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![[Post New]](/templates/default/images/icon_minipost_new.gif) 15 Jul 2007 22:14:45 IST
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Hello, Another ques that i stumbled across this morning is..... A hemisphere of radius R is placed in an uniform electric field E wid its axis perpendicular to the electric field E . What is the electric flux thru the curved surface? Plzzz.. reply soon.
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15 Jul 2007 22:23:53 IST
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Come on I can't beleive that noobody can answer this..........Any Ideas...I would be greatful.
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15 Jul 2007 23:02:43 IST
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This question has to be dealt in terms of lines of force of electric field.If you draw the figure carefully the you will notice that the number of lines of force entering the hemisphere is equal to number of lines of force leaving it.So net flux is zero.For more refer to resnick(good expl.)
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Asmit is right
Partition the hemisphere into two quarter spheres, one through which the lines of electric field come in and the other through which electric field lines come out. Consider an arbitrary line of electric field cutting the hemisphere surface at two elementary area, each of area dS.
Electric flux through the two elementary surfaces
d = (E.en) dS+ (E.en') dS=E cos dS + E cos( -)dS = 0
 = 0
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16 Jul 2007 17:49:57 IST
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Loads of thanks to both of u......
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If u agree wid me do rank me..... |
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