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Electricity

Hot goIITian

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16 Aug 2009 17:09:19 IST
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Current electricity
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Ques1)

Each resistance is r . Show that the equivalent resistance b/w points A and B is zero (in the above figure).

Ques2) In the circuit shown, Find the current in the 3 ohm resistance.

Ques3) Five identical lamps each having reisistance R= 1100 ohm are connected to 220 V as shown below.Show that the reading of the ideal ammeter is 3/5 I A.

Ques4) A,B,C,D are four points in succession at equal distances along a wire and A,B,C,D are also joined by other two wires of the same length as the distance b/w those pairs of point measured along the original wire. A current I enters the network thus, formed at A and leaves D. Find the lectric current in BC.


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sarang's Avatar

Blazing goIITian

Joined: 20 Nov 2008
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16 Aug 2009 17:23:09 IST
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1)5r/14


Hot goIITian

Joined: 28 Jul 2009
Posts: 165
16 Aug 2009 17:32:46 IST
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Ist answer is zero. It is given in the ques itself. You have to show that.
eragon24's Avatar

Blazing goIITian

Joined: 14 May 2009
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16 Aug 2009 17:43:55 IST
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 first answer will be 0 bec u have short circuited the point a and b.....current instead of moving through resistance will move through the wire   with no resistors........

Soumen Goswami's Avatar

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Joined: 10 Apr 2007
Posts: 1777
16 Aug 2009 22:21:31 IST
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First answer is zero, as A and B are shorted.


Scorching goIITian

Joined: 6 Jun 2009
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16 Aug 2009 22:50:47 IST
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yup. In I answer, both A and B are on equal potential and there is no net potential difference therefore, the circuit is shorted and no charge'll flow through resistors. Now I'm trying next parts.

Scorching goIITian

Joined: 6 Jun 2009
Posts: 292
16 Aug 2009 22:56:59 IST
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Answer III: I did it in this way: before ammeter, net resistance is R/2 and after it, it is R/3. Now circuit will show, two resistors with a ammeter connected in series with R/3 resistor. Assuming : I (A) + I (B) will flow through 220 V source, then : I (B)R/3 = 220. Now: I (B) = 220*3/R which is equal to 3/5 A. and I (B) is the current which will be reflected by needle of ammeter.. hence solved. cheer.

Scorching goIITian

Joined: 6 Jun 2009
Posts: 292
16 Aug 2009 22:58:13 IST
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Answer II: Where is the source: at least a source should be there, which will give reason to find direction of current flowing through wires.. anyhow.. if anyone able to do this.. do nudge me. ..



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