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Electricity

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31 May 2007 17:16:54 IST
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differentiation
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if g is the inverse function of f and f '(x)=1/1+x5 then g '(x) is equal to


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T RAHUL N THIRUGNANAM's Avatar

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Joined: 23 Mar 2007
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31 May 2007 17:21:48 IST
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integrate f'(x) u will get f(x).put f(x)=y and find x in terms of y.replace y with x and differentiate to ge g'(x)

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31 May 2007 17:28:17 IST
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please solve
T RAHUL N THIRUGNANAM's Avatar

Cool goIITian

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31 May 2007 17:32:44 IST
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first rate me only then i will giv the solution
vizay soni's Avatar

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31 May 2007 18:17:09 IST
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calculus-> what is d/dx of x!
! means factorial


choice->a)ln x
b)ln x+ln (x-1)+ln (x-2)+.........
c)1
d)none of these
CyBorG's Avatar

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Joined: 6 Jan 2007
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1 Jun 2007 15:13:18 IST
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Given g is the inverse function of f.
 
So g(x)=f -1(x)
 
or  f(g(x))=x
 
Now differentiate this wrt x.
 
ie    f '(g(x)) g '(x)=1...................(1)
 
It is also given that f '(x)=1/(1+x5
 
So f '(g(x))=1/(1+(g(x))5)
 
Substituing this in (1) we get,
 
g '(x)/(1+(g(x))5)=1
 
or  g '(x)=1+(g(x))5



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