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Electricity

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13 Mar 2008 15:58:49 IST

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y do we represt as electric as _{[q ]}_{[ o]} f/q??

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ankur khurana

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13 Mar 2008 17:30:23 IST

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it is when a test charge q is represented as q and is taken to Q (that is positive charge....) and so that q does not affect or apply any force q->0 and hence electric field ....i.e force per unit charge is represented as f/q and correctly represneted as q

0 f/q

umar banday

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13 Mar 2008 18:08:54 IST

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it is becoz if q (test charge) has mag. > 0 then the source charge will be displaced i.e moved due to the electric field of the test charge..and the net field due to source charge will not be correct.....so we take the mag. of the test charge as tends to zero (which is not possible....we only assume it)....ok

Gaurav |spideyunlimited| Ragtah

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13 Mar 2008 18:20:58 IST

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So that the charge in consideration has negligible electric field of its own, as compared to the field in which it is being moved

Krishna Gopal Singh

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15 Mar 2008 08:54:32 IST

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Perfect answer by everyone. The idea is that test charge should not disturb the configration of the system.

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