if one of the sides has a charge Q the other side must also hav a charge Q.
so therefore the e field on both sides is is of the same mag.
electric field due to a charged metallic slab at any pt outside it is given by
E=

/2
o where

is the surface charge density.
therefore

= Q/area= Q/L
2 hence E= Q/2
oL
2 (note- this is applicable only for a pt nearer to the centre, ie it is not app for pts at the sides of the slab)
at any pt inside the slab E=0