| Author |
Message |
![[Post New]](/templates/default/images/icon_minipost_new.gif) 7 Feb 2007 23:07:01 IST
|
|
|
Two concentric spherical spheres of radii a & b (b>a) having charges q & Q respectively, then what is the charge on inner side of sphere of radius b ? explain.
|
<TABLE CELLSPACING="1" CELLPADDING="1" BORDER="0">
<TR><TD>
     
<DIV ALIGN="right">Glitter Graphics</DIV></TD></TR></TABLE>
|
|
|
|
![[Post New]](/templates/default/images/icon_minipost_new.gif) 7 Feb 2007 23:10:07 IST
|
|
|
hi,
the inner side of the radius b would be -q if the shells are made of conducting material .i guess even otherwise its true
|
this reply: 0 points
(with 0 
in 0 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
![[Post New]](/templates/default/images/icon_minipost_new.gif) 7 Feb 2007 23:11:21 IST
|
|
|
r u sure tere r 2 concentric spheres.not shells?
|
this reply: 0 points
(with 0 
in 0 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
![[Post New]](/templates/default/images/icon_minipost_new.gif) 7 Feb 2007 23:16:14 IST
|
|
|
they r hollow spheres (sheel) & kusum i need an explanation
|
<TABLE CELLSPACING="1" CELLPADDING="1" BORDER="0">
<TR><TD>
     
<DIV ALIGN="right">Glitter Graphics</DIV></TD></TR></TABLE>
|
this reply: 0 points
(with 0 
in 0 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
![[Post New]](/templates/default/images/icon_minipost_new.gif) 7 Feb 2007 23:19:11 IST
|
|
|
well manmadha or whatever state the question better
if they are solid spheres then one sphere will be part of another and if they r of conducting material then the total charge will get nullified
if they are shells separated by vaccume then there are further possibilities
if the thickness of shells is considered then what kusum says is correct. if the shells are made out of positively charged particles only and have negligible thickness...then the charge on inner surface of b will be +Q only
|
tomorrow theres another possibility |
this reply: 0 points
(with 0 
in 0 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
![[Post New]](/templates/default/images/icon_minipost_new.gif) 7 Feb 2007 23:24:28 IST
|
|
|
as far as kusums solution is considered....she has considered that the shperes have a thickness
thus if the outer part of sphere has positive charge and even inside the bigger shpere there is a positively charged surface then the inner surface of the bigger sphere is bound to have -Q charge due to induction...the positive surface inside B will attract all the electrons towards the inward surface....
|
tomorrow theres another possibility |
this reply: 5 points
(with 1 
in 1 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
![[Post New]](/templates/default/images/icon_minipost_new.gif) 7 Feb 2007 23:29:08 IST
|
|
|
i know dat it attracts ,but why it is only -q which appears on innerpart of sphere?
|
<TABLE CELLSPACING="1" CELLPADDING="1" BORDER="0">
<TR><TD>
     
<DIV ALIGN="right">Glitter Graphics</DIV></TD></TR></TABLE>
|
this reply: 0 points
(with 0 
in 0 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
![[Post New]](/templates/default/images/icon_minipost_new.gif) 7 Feb 2007 23:31:06 IST
|
|
|
hi,
the concept behind the prob is inside a conducting material electric field is always zero so u can take net charge to be zero .
keepin the smae in mind,
the inner surface of the shell will have zero charge ,
its outer surface q
outer shellll inner surace -q to make net charge zero inside it
its outer surface q+q to maintain chrage constant
.i hope im clear
|
this reply: 0 points
(with 0 
in 0 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
![[Post New]](/templates/default/images/icon_minipost_new.gif) 7 Feb 2007 23:37:15 IST
|
|
|
yes kusum,but here electric field is not zero inside outer shell because there is another shell inside.i.e there is Electric field between a & b
|
<TABLE CELLSPACING="1" CELLPADDING="1" BORDER="0">
<TR><TD>
     
<DIV ALIGN="right">Glitter Graphics</DIV></TD></TR></TABLE>
|
this reply: 0 points
(with 0 
in 0 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
![[Post New]](/templates/default/images/icon_minipost_new.gif) 7 Feb 2007 23:39:22 IST
|
|
|
hi ,
just check the net charge apply gauss law E=Q0 / epsilon0
|
this reply: 0 points
(with 0 
in 0 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
![[Post New]](/templates/default/images/icon_minipost_new.gif) 7 Feb 2007 23:44:11 IST
|
|
|
manmadha, +Q and -Q must add up to give 0 total charge if B has uniform charge +Q spread across its outer surface then it has to have -Q charge on its inner surface as there is no other surface for electrons to go
and as the sphere inside B also has uniform positive charge across its surface it will attract all the -Q charge developed on the inner surface of B uniformly
are you getting me??
|
tomorrow theres another possibility |
this reply: 0 points
(with 0 
in 0 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
![[Post New]](/templates/default/images/icon_minipost_new.gif) 7 Feb 2007 23:49:06 IST
|
|
|
hi ,
mamadha y dont u check HC VERMA FOR GAUSS LAW APPLICTION
then within no time u'lll undersand my slon
|
this reply: 0 points
(with 0 
in 0 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
![[Post New]](/templates/default/images/icon_minipost_new.gif) 7 Feb 2007 23:49:14 IST
|
|
|
yes the net charge will be q if gaussian surface is jus inside the outer shell
|
<TABLE CELLSPACING="1" CELLPADDING="1" BORDER="0">
<TR><TD>
     
<DIV ALIGN="right">Glitter Graphics</DIV></TD></TR></TABLE>
|
this reply: 0 points
(with 0 
in 0 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
![[Post New]](/templates/default/images/icon_minipost_new.gif) 7 Feb 2007 23:53:34 IST
|
|
|
actuaaly the ques,. is a part of example-3 page-137 in HCV
|
<TABLE CELLSPACING="1" CELLPADDING="1" BORDER="0">
<TR><TD>
     
<DIV ALIGN="right">Glitter Graphics</DIV></TD></TR></TABLE>
|
this reply: 0 points
(with 0 
in 0 votes ) [?]
|
|
| |