|
|
|
|
|
| Author |
Message |
![[Post New]](/templates/default/images/icon_minipost_new.gif) 28 Jun 2007 13:57:16 IST
|
|
|
A battery of emf 100 V and a resistor of 10 k ohm are joined in series . This system is used as a source to supply current to an external resistance R . If R is not greater than 100ohm , the current through it is constant upto two significant digits . Find its value
|
|
|
|
|
|
|
|
The current is
i = 100/(1000+R)
R = (100/i) - 1000
R  100
(100/i) - 1000 100
i  1/11
i 0.090909......
As i is constant upto 2 places of decimal,
i = 0.09 A
|
|
this reply: 10 points
(with 2 
in 2 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
|
|
|
|
|
|
|
Moderation Team
![[Up]](/templates/default/images/icon_up.gif "[Up]"){kind=icon}
