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Electric field of a charged plate...
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A charged metal plate placed vertically has electric fields on either side as shown in figure:
10 V/m to the right and 8 V/m to the left.
So the charge density on the metal plate is:
1. 2

2. 4

3. 10

4. zero
[
=permittivity of the plate]
=permittivity of the plate]ps: I think the charge density should b zero, since a charged metal plate produces a uniform electric field..
/
in the entire region[
=charge density].
/
in the entire region[
=charge density].So in no way can the field b non uniform, lest there are some xternal charges.
Please post ur answers wid xplaination....
Comments (4)
NAKUL
Cool goIITian

Joined: 19 Feb 2008
Posts: 72
26 Mar 2008 11:11:19 IST
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the image can't b uploaded..but yall can do widout the image...
remember its a charged plate nd not a charged sheet...
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26 Mar 2008 16:09:18 IST
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consider that this sheet is placed between two other plates with charge densities of +10 e on one side and -8e on the other, then on either side you may get electric fields equal to 10 V/m and 8 V/m.
In that case the net charge density of the block(Plate) will be 2e.
Here e stands for permeability.
In that case the net charge density of the block(Plate) will be 2e.
Here e stands for permeability.



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