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Electricity

NAKUL's Avatar
Cool goIITian

Joined: 19 Feb 2008
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26 Mar 2008 11:06:09 IST
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Electric field of a charged plate...
None

A charged metal plate placed vertically has electric fields on either side as shown in figure:
10 V/m to the right and 8 V/m to the left.
So the charge density on the metal plate is:
1. 2
2. 4
3. 10
4. zero
[=permittivity of the plate]
 
ps: I think the charge density should b zero, since a charged metal plate produces a uniform electric field../ in the entire region[=charge density].
So in no way can the field b non uniform, lest there are some xternal charges.
Please post ur answers wid xplaination....


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Comments (4)

NAKUL's Avatar

Cool goIITian

Joined: 19 Feb 2008
Posts: 72
26 Mar 2008 11:11:19 IST
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the image can't b uploaded..but yall can do widout the image...
remember its a charged plate nd not a charged sheet...
gokul subramanian's Avatar

Blazing goIITian

Joined: 28 Jan 2008
Posts: 1451
26 Mar 2008 11:15:43 IST
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2o
NAKUL's Avatar

Cool goIITian

Joined: 19 Feb 2008
Posts: 72
26 Mar 2008 12:45:37 IST
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buddy it d b preferable if u give ur approach....
i m nt quite sure of either answers..

Hot goIITian

Joined: 10 Mar 2008
Posts: 186
26 Mar 2008 16:09:18 IST
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consider that this sheet is placed between two other plates with charge densities of +10 e on one side and -8e on the other, then on either side you may get electric fields equal to 10 V/m and 8 V/m.

In that case the net charge density of the block(Plate) will be 2e.
Here e stands for permeability.



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