|
|
|
|
|
| Author |
Message |
![[Post New]](/templates/default/images/icon_minipost_new.gif) 5 Jul 2007 10:06:35 IST
|
|
|
a ball of mass 1 gm , charge 10 to power -8 coulomb moves from a point A whose potetial is 600 V to the point B whose potetial is 0 V , if the velocity of the ball at B is 20m/s what is its velocity at A ? plz give explanation.....
|
|
|
|
5 Jul 2007 10:40:51 IST
|
|
|
work done to move the ball is equal to the change in momentum...so equate q(Vb-Va) and m1v1 + m2v2..from here find v1,which is the rquired answer..hope u got it...cheers!
|
never give up in life.keep trying till you succeed.don't forget to rate my answers if u find them to be correct as it will only boost my confidence.... |
this reply: 2 points
(with 0 
in 1 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
5 Jul 2007 12:19:32 IST
|
|
|
System: charge + the system causing the potential change
By work energy theorem,
 E = Wext
As there are no external forces
 K + U = 0
(1/2)(0.001)(v2 - 400) + (10)(10)-8(0 - 600) = 0
Find v from this
|
|
this reply: 0 points
(with 0
in 0 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
|
|
|
|
|
|
|
Moderation Team
![[Up]](/templates/default/images/icon_up.gif "[Up]"){kind=icon}
