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22 Mar 2008 16:50:01 IST

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-Q charge are placed on the vertices of a square .a q charge is then placed at the center of it. system is in equilibrium then find the value of q.... please ans this

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Ananth Patri

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22 Mar 2008 16:52:12 IST

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it can be anything.....as at centre the net force is zero....right....

dheer Bhatia

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22 Mar 2008 16:58:27 IST

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yup he s right

force due to each will cancel

ameya sahasrabudhe

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22 Mar 2008 16:59:30 IST

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lol anant patri........... u need to think a bit deeper.
wont the -Q charges repel each other?
balance the force on any one vertex's charge.
q=(2root2 +1)Q/4

NITESH BASKARAN

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22 Mar 2008 19:43:13 IST

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the central charge is always in equilibrium but the charges at the vertices wont always be
force on a vertex charge due to similar charges = (1/2+ root 2)F
where F = kQ^2/r^2
force due to positive charge at the centre = 2kq^2/r^2 = (1+2 root 2) x kQ^2/(2r^2)
hence q = (1+2root 2)Q/4

suresan

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22 Mar 2008 19:54:28 IST

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q/2 = +2root2Q

Karthik M

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22 Mar 2008 20:31:38 IST

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Find the x and y components of the forces acting at the center due to each of the charges, and then equate each of the components individually to zero, and thus get the value of q

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