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Electricity

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4 Jul 2009 19:16:37 IST

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Two particles A anb B ,each having a charge Q are palced at a distance d apart. where should a particle of charge q be palced on the perpendicular bisector of AB so ths it experiences maximum force? What is the magnitude of this max force?

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dc16

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4 Jul 2009 19:17:33 IST

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d / (root 2)

Nikhil Bole

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4 Jul 2009 19:22:29 IST

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Plz explain it

dc16

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4 Jul 2009 19:27:18 IST

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DUDE, take any distance x and find the force on the charge in terms of x.

Then diffrentiate it in terms of x and put it equal to zero and find x .

Then after finding x , put it in the force eqn to find the maximum force..!!

CHEERS ..!!

Nikhil Bole

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5 Jul 2009 13:53:51 IST

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I have already done it but couldn't get the answer..and by the way ur answer is wrong......

VARUN RAJ

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5 Jul 2009 21:08:27 IST

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so let it be at a distance x from the half of line ab

the force will be and this will be along the hpothenese the horizontal components of te forces will cancel each other out

and the total force will be the sum of the vertical component of the forces =

and here r²=x²+d²/4 and costhetha=

solving we get Qx/(x²+d²/4)^3/2

for MAXIMUM value d/dx x/(x²+d²/4)^3/2=0

solve and get the answer

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