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![[Post New]](/templates/default/images/icon_minipost_new.gif) 23 Jun 2007 11:58:19 IST
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2 concentric spheres of radii R and r have similar charges with equal surface densities .what is the electric potential at their common centre
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{(k )/ R3} + {(k )/ r 3}
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 25 Jun 2007 17:25:21 IST
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Potential due to sphere at the center. =3KQ/2R [ r being the radius of the sphere] .: for smaller one V1=3KQ/2r =3K(  4pir^2)/2r =12K  pi*r similarly potential due to bigger one =12K  pi*R So net potential = 12K  pi(R+r) = [3 (R+r)] / o
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 2 Jul 2007 11:02:13 IST
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joy francis is absolutely rit but let ,me add sumthing...surface charge density is charge per unit surface area..and surface charge density of the two spheres r same..and their radius is given and hence we can find charges on each of them..so potential is simply their sum of potentials
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a 2nd year IIT DELHI student, doing B.Tech in chemical engineering |
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 2 Jul 2007 13:22:50 IST
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Answer provided by Joy is wrong.... As spheres r conc. therefore they must be hollow and for hollow sphere pot is constant and same as on the surface Now find the pot. by each sphere and add them...
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