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NAVIO (49)

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2 concentric spheres of radii R and r have similar charges with equal surface densities  .what is the electric potential at their common centre

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anchal_1991 (237)

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{(k)/R3} + {(k)/r 3}

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joyfrancis (1504)

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Potential due to sphere at the center.
=3KQ/2R [ r being the radius of the sphere]
 
.: for smaller one
V1=3KQ/2r
    =3K(4pir^2)/2r
    =12Kpi*r
similarly potential due to bigger one
=12Kpi*R
 
So net potential = 12Kpi(R+r)
                       
= [3(R+r)] / o 

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deepak_agarwal (539)

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joy francis is absolutely rit but let ,me add sumthing...surface charge density is charge per unit surface area..and surface charge density of the two spheres r same..and their radius is given and hence we can find charges on each of them..so potential is simply their sum of potentials

a 2nd year IIT DELHI student, doing B.Tech in chemical engineering
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maverick83 (36)

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Answer provided by Joy is wrong....
As spheres r conc. therefore they must be hollow and for hollow sphere pot is constant and same as on the surface
Now find the pot. by each sphere and add them...
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